$$ \newcommand{\uex}{{u_{\small\mbox{e}}}} \newcommand{\half}{\frac{1}{2}} \newcommand{\tp}{\thinspace .} \newcommand{\Oof}[1]{\mathcal{O}(#1)} $$

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The Backward Euler scheme

We apply the Backward Euler scheme to each component equation: $$ [D_t^- u = v]^{n+1},$$ $$ [D_t^- v = -\omega u]^{n+1} \tp $$ Written out: $$ \begin{align} u^{n+1} - \Delta t v^{n+1} = u^{n},\\ v^{n+1} + \Delta t \omega^2 u^{n+1} = v^{n} \tp \end{align} $$ This is a coupled \( 2\times 2 \) system for the new values at \( t=t_{n+1} \)!

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