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Operator notation; ODE

With [DtDtu]n as the finite difference approximation to u(tn) we can write [DtDtu+ω2u=0]n

[DtDtu]n means applying a central difference with step Δt/2 twice: [Dt(Dtu)]n=[Dtu]n+12[Dtu]n12Δt which is written out as 1Δt(un+1unΔtunun1Δt)=un+12un+un1Δt2.

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