Processing math: 100%
The central difference for u′(t) (1)
u(tn+12)−u(tn−1/2)=u′(tn)Δt+124u‴(tn)Δt3+O(Δt5).
By collecting terms in [Dtu]n−u(tn) we find Rn to be
Rn=124u‴(tn)Δt2+O(Δt4),
Note:
- Second-order accuracy since the leading term is Δt2
- Only even powers of Δt