$$ \newcommand{\uex}{{u_{\small\mbox{e}}}} \newcommand{\Aex}{{A_{\small\mbox{e}}}} \newcommand{\half}{\frac{1}{2}} \newcommand{\Oof}[1]{\mathcal{O}(#1)} $$

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The Leapfrog scheme

Idea: $$ \begin{equation} u'(t_n)\approx \frac{u^{n+1}-u^{n-1}}{2\Delta t} = [D_{2t} u]^n \end{equation} $$

Scheme: $$ [D_{2t} u = f(u,t)]^n$$ or written out, $$ \begin{equation} u^{n+1} = u^{n-1} + \Delta t f(u^n, t_n) \tag{40} \end{equation} $$

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